This is the online extension of our classroom this semester (2007 Fall Term) at the SVRSS. The content here is being created by real students in a real classroom. Enjoy learning from and with each other...

Friday, September 21, 2007

Why Are There Rules in Croquet?

Please post solutions below as comments, or feel free to create a post indicating your number for your team...



Cheeze Whiz said...

7. Pie; 20 less than 3 times ice cream
500 calories total

let x= number of calories in pie
let y= number of calories in ice cream

l1: x+y=500
l2: 3y-20=x

l1: y=500-x
l2: y=(x+20)/3
therefore; (x=370, y=130)

Katlynn.* said...

Question #4:

Let x = The First Number
Let y = The Second Number which is five more then two times the first number

From the information above we know that:
L1: x + y = 44
L2: 2x + 5 = y

Next we have to rearrange the equations so that they line up:
L1: x + y = 44
L2: 2x - y = -5

Now we multiply L1 by (-1) so that we can preform the Elimination Method:
L1: -x - y = 44

Now to preform the Elimination Method we subtract L1 from L2 to get:
3x = 39
x = 13

Now that we know what x is we plug it into either L1 or L2 to figure out what y is(in this case we will use L2):
2x + 5 = y
2(13) + 5 = y
26 + 5 = y
31 = y

Therefore we know that the first number in the equation is thirteen and the second number is thirty one .

BettyDoll said...

Question #1: The sum of two numbers is 90. Their difference is 18. Find the numbers.

let x = one of the numbers
let y = the other number

L1: x + y = 90
L2: x - y = 18

L1: y = 90 - x
L2: -y = 18 - x
y = (18 - x) / 1

After we graph the lines and find the intersection, we know one of the numbers (x) is 54 and the other number (y) is 36.

* J a n e l l e * said...

Joke Sheet, Pg.166 #2
The second of two numbers is 4 more than the first. The sum of the numbers is 56. Find the numbers.

Step One:
Let a = The first number.
Let b = The second number that is greater than 4 of the first number.

Step Two:
L1: a+b= 56
L2: b= a+4

Step Three:
+ b=a+4
2b= 60
(2b)/2= 60/2
b= 30

(Substitute 30 in for b)
a+b = 56
a+(30)= 56
a+30-30= 56-30
a= 26

Step Four:
The first number equals 26. The second number that is four more than the first number is 30 therefore the sum of the two numbers are 56.

This post was posted by: * J a n e l l e * and :chevy